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作者 Vulpix 在 PTT [ Math ] 看板的留言(推文), 共7171則
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5F→: i的重點是非空,其實不找(0,0,0)也沒關係,(3,0,5)02/14 22:21
6F→: 也可以02/14 22:21
4F→: 這讓我想起一篇0^0的文01/16 20:41
6F→: 你想問的是 generalized eigenvector10/17 21:16
5F→: 題目本來大概是(k-1)*k!/2^(k+1)吧08/03 00:47
1F推: 就是這個了!07/27 01:47
8F→: 先硬分解出兩個根-1,-1 剩下的再用x^2=2x-3降次做?07/27 00:20
9F→: f(-1)=-2,然後f(c)f(d)=(2c-6)(2d-6)=4(3^2-2*3+3)07/27 00:23
10F→: 這個方法應該比較普通,雖然最後面有多用一點技巧07/27 00:24
6F→: by平行公設,沒有平面三角形的內角和會是270度。07/27 00:28
7F→: 如果你要一個曲面上的三角形:赤道,0度經線,90度經07/27 00:30
8F→: 線就可以圍出你想要的三角形了。所以R^3中的球面就07/27 00:31
9F→: 夠了,不用去R^4找。07/27 00:31
2F→: first fundamental form吧07/27 00:34
1F→: 第一個問題...寫得很讓人看不懂04/04 16:54
2F→: 根據猜測應該是類似於:若f(x)=x^3-x04/04 16:55
3F→: f'(x)=3x^2-1, f"(x)=6x04/04 16:56
4F→: 極值發生在x=1/3^0.5及x=-1/3^0.504/04 16:58
5F→: 然後去算f"(1/3^0.5)=2*3^0.504/04 16:59
6F→: 沒有未知數是因為已經找到critical point代入了04/04 16:59
7F→: 第二個問題就...想辦法畫出來吧04/04 17:00
3F→: 國中方法限定...剛剛至少做了3條輔助線@@04/04 14:18