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作者 Vulpix 在 PTT [ Math ] 看板的留言(推文), 共7235則
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1F→: 隨便找個反例:T=I、T'=2I。02/23 12:51
2F→: 如果det(T)不是0,那R=T'*T^-102/23 12:55
3F→: 如果是三維空間的話,解出R的eigenvalue和02/23 12:56
4F→: eigenvector,1-eigenspace是你要的axis,而另外02/23 12:57
5F→: 兩個eigenvalue是e^(ia)的形式,a就是你要的theta02/23 12:58
6F→: 算到這裡還有個正負號的問題,這個問題就不大了。02/23 13:00
1F推: 好像是步驟寫錯,(6)應該作VX直線。02/15 17:24
2F→: 用到的性質是:正焦弦長=4c。02/15 17:25
5F→: i的重點是非空,其實不找(0,0,0)也沒關係,(3,0,5)02/14 22:21
6F→: 也可以02/14 22:21
4F→: 這讓我想起一篇0^0的文01/16 20:41
6F→: 你想問的是 generalized eigenvector10/17 21:16
5F→: 題目本來大概是(k-1)*k!/2^(k+1)吧08/03 00:47
1F推: 就是這個了!07/27 01:47
8F→: 先硬分解出兩個根-1,-1 剩下的再用x^2=2x-3降次做?07/27 00:20
9F→: f(-1)=-2,然後f(c)f(d)=(2c-6)(2d-6)=4(3^2-2*3+3)07/27 00:23
10F→: 這個方法應該比較普通,雖然最後面有多用一點技巧07/27 00:24
6F→: by平行公設,沒有平面三角形的內角和會是270度。07/27 00:28
7F→: 如果你要一個曲面上的三角形:赤道,0度經線,90度經07/27 00:30
8F→: 線就可以圍出你想要的三角形了。所以R^3中的球面就07/27 00:31
9F→: 夠了,不用去R^4找。07/27 00:31
2F→: first fundamental form吧07/27 00:34