作者查詢 / WINDHEAD
作者 WINDHEAD 在 PTT [ Math ] 看板的留言(推文), 共560則
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4F→:e^{iπ}一旦被定義成一個複數,他就必須是 -107/14 11:50
27F推:wohtp說的是對的,舉個數學的例子 ,群的semiproduct07/08 04:51
28F→:(半直積)裡面,一個元素可以分解成兩個分量,可是07/08 04:52
29F→:這個分解不是唯一的,他依賴於某種預先的選擇07/08 04:52
30F→:所以x,y運動獨立是因為你使用向量空間作為描述的07/08 04:53
31F→:數學語言,然而符不符合物理現象是另外一個故事07/08 04:54
19F→:運動獨立性可以看成公設沒錯阿,你怎麼知道X軸跟07/07 02:50
20F→:Y軸沒有隱密的"糾纏"?07/07 02:50
16F推:兩個一起修不就解決了07/08 03:39
20F→:數學沒有諾貝爾獎,可是有阿貝爾獎,是最高榮譽終身成就獎06/26 11:30
2F→:我就是不爽推文啦怎樣06/04 22:15
6F→:樓上織織別這樣 惜惜06/05 06:24
3F推:雖然不知道你要的基本證明到底有多基本,不過既然你06/04 08:57
4F→:提到well order那就可以這樣想: 給定整數a,b06/04 08:58
5F→:考慮 S={am+bn|m,n整數}. 令d為S中最小的正整數06/04 08:59
6F→:任取 S 中元素 t, 考慮除法 t=dq+r 可知 0<=r<d06/04 09:01
7F→: r=t-dq 所以 r 也是S中的元素 , 故r=006/04 09:02
8F→:所以 d 整除 S中所有元素,簡單說 d 是a,b的公因數06/04 09:04
9F→:但是 d 本身也是S的元素,所以任何a,b的正公因數都要06/04 09:04
10F→:整除 d, 所以不能比d大,也就是說d是a,b的最大公因數06/04 09:04
16F→:負數沒有影響基本上可以不管他,你只看一邊而已06/04 09:53
17F→:S的定義就必然會包含一堆正數了....負的不用管他06/04 09:53
18F→:因為你實際上是靠係數 m,n 的正負來調節的06/04 09:54
19F推:有沒有更基本的我就不懂了,不過你可以看出這個方法06/04 09:56
20F→:很迂迴,但反而得到一些更有結構感的東西06/04 09:57
21F→:這個故事裡面重要的是S而不是a,b. 有時候不同的a,b06/04 09:58
22F→:會給出同樣的S集合....那個S才是重要的06/04 09:58
29F→:well-order只適用於正整數...不過這種抽象的東西可以06/04 10:13
30F→:跳過啦,用直覺想正整數集合一定有最小元素就好啦06/04 10:14
31F→:如果要抽象的話我當初就直接說 S 是a,b生成的理想了06/04 10:14
34F推:XD06/04 10:23
4F推:06/03 03:00
10F推:06/03 03:05
1F→:隨便哪個都可以,都一樣05/30 23:01