[中學] 方程式
Let
[1 2] [1]
A = [3 4] b =[1]
[5 6] [1]
Solve the linear system Ax = b via the normal equation.
這題用看的就知道 x =(-1,1) 但是過程...不知道該怎去寫
是該任取2個解去解 再將解帶入第3個嗎
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推
12/01 16:50, , 1F
12/01 16:50, 1F
[1 2 0 | 1]
[3 4 0 | 1]
[5 6 0 | 1] 補一行下去高斯嗎?
※ 編輯: c96a111 來自: 111.242.5.90 (12/01 17:03)
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12/01 17:03, , 2F
12/01 17:03, 2F
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12/01 17:04, , 3F
12/01 17:04, 3F
※ 編輯: c96a111 來自: 111.242.5.90 (12/01 17:05)
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12/01 20:49, , 4F
12/01 20:49, 4F
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12/01 20:49, , 5F
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12/01 20:50, , 6F
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12/01 20:51, , 8F
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12/01 20:51, , 9F
12/01 20:51, 9F
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12/01 21:00, , 10F
12/01 21:00, 10F
我想說很簡單 用看的就出來 還打算畫一隻眼睛代表過程 "<(@)>"
※ 編輯: c96a111 來自: 111.242.5.90 (12/01 21:02)
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12/01 21:06, , 11F
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12/01 21:06, , 12F
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12/01 21:08, , 13F
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12/01 21:29, , 14F
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12/01 21:56, , 15F
12/01 21:56, 15F
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12/01 22:00, , 16F
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12/01 22:12, , 17F
12/01 22:12, 17F
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