[中學] 方程式
令y=x^2
x^4 + (m+2)x^2 + (m+5) = 0
有兩相異實根兩相異虛根
=> y^2 + (m+2)y + (m+5) = 0
則上面方程是有一正根,一負根 <==想請問為什麼?
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