作者查詢 / profyang
作者 profyang 在 PTT [ Math ] 看板的留言(推文), 共376則
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5F推:這是不可逆的基本性質之一...存在非零解09/21 17:03
22F推:C_4*3 = ( A_2*3 ) * ( B_4*2 )<=這怎麼乘?你教我09/17 23:38
25F推:我終於看懂了..他想算的好像是B*A*[1;0;1]09/18 00:50
26F→:所以是4*2矩陣乘上2*3矩陣再乘上3*1矩陣...09/18 00:51
27F推:靠突然好佩服自己居然看得懂09/18 00:53
1F推:令u=1/√(1+x^2)08/12 13:30
2F推:要用你的方法也可 你那個化簡一下就變成08/12 13:39
3F→:∫1/(sin^2θ*cos^2θ)*sinθdθ令cosθ=u就跟我1F推08/12 13:40
4F→:的一樣了08/12 13:40
2F推:馬的word內建方程式真的醜爆 他到底幾時要改好看一點08/09 13:04
2F→:我對他命題的理解是:If AB=BA for any B, then A=kI08/02 22:04
3F→:但1F你的證明好像是If A=kI, then AB=BA for any B08/02 22:05
5F→:等等 我這證明還少一個步驟 他的命題應該是對的08/02 22:10
3F推:我好像突然看懂你的證明了 你是把B拆成n^2個的基底08/02 22:17
4F→:這樣跟我的證明是等價的08/02 22:17
1F推:這沒有證明A為啥一定要是kI吧?08/02 20:45
12F推:A=0*I=0還不是單位矩陣的常數倍?08/02 21:25
16F推:什麼可以交換...2D旋轉矩陣的幾何特性是結合律吧08/02 21:55
19F→:對不起我上面的推文錯了 不過你這樣講還是不對 B是08/02 22:01
20F→:任意矩陣不一定是旋轉矩陣08/02 22:01
21F→:所以A是旋轉矩陣並不一定滿足他的命題08/02 22:01
9F推:不定積分沒有一般函數解 定積分的話 Matlab是你的好06/06 15:10
10F→:朋友~^__^06/06 15:11
6F推:第二種方法比較好...還有樓上 f(0)都沒定義了 要重新05/21 08:35
7F→:把f(x)定義成連續函數才行05/21 08:36
8F→:解法二直接寫x^x=exp(ln(x^x))=exp(xln(x))就好05/21 08:37
9F→:總覺得你過程太詳細了XDD不是不好 但看了有點煩XDD05/21 08:39