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作者 Vulpix 在 PTT [ Math ] 看板的留言(推文), 共7235則
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1F→: 這是一個很寬鬆的估計:05/10 23:19
2F→: BM+NO+PD > BN+NO+OD ≧ BD = sqrt(61) > 15/205/10 23:21
1F→: 要能圍成三角形,3到2105/01 10:29
3F→: 當成x的多項式(把y當成常數)配平方看看。04/30 00:34
5F→: 其實因為那個式子沒有極限,所以要用別種方法(例如04/29 23:41
6F→: 樓上L大所說的方式)去算收斂半徑。04/29 23:41
5F→: 會不會出現樓上說的情況還是得看首位數的。04/28 16:11
16F→: 推~04/28 16:37
4F→: 弦心距用海龍公式算出來,就可以了。04/26 20:01
7F→: 有兩個扇形要算,小圓的圓心角比較小。04/26 20:24
8F→: x,r,R圍成一個三角形,弦心距d可以用海龍公式算。04/26 20:24
9F→: R^2*arccos(d/R) - r^2*arccos(d/r) - xd04/26 20:27
10F→: 最後那項是兩個"x,r,R圍成的三角形"04/26 20:27
1F→: 不是04/26 00:42
2F→: 如果落在一個平面上,就一定是條橢圓。04/26 00:44
3F→: 先別說橢圓弧長要用橢圓積分來表示...04/26 00:46
4F→: 出發和返回的兩條線交角60度,所以不是橢圓(平滑)。04/26 00:48
6F→: 你想像把展開的扇形再沿著那條直線剪開,04/26 14:17
7F→: 然後再照原本圓錐的彎曲方式黏回去,04/26 14:18
8F→: 兩邊各一個30度,剛好60度。04/26 14:19
10F→: 感覺比較像二進制吧。2^k都在span({1})裡才對啊。04/25 23:48
1F→: 從你找到的全等繼續做:04/21 02:49
2F→: ∠ABF=∠ADF => AFBD四點共圓 => ∠AFD=∠ABD=60度04/21 02:53
3F→: 另一半一樣做法。04/21 02:57
4F→: 覺得四點共圓很不舒服的話可以用相似形換掉:04/21 02:58
5F→: 稱呼AB和CD的交點為P,△PAD~△PFB(AA相似)04/21 03:02
6F→: PA/PF=PD/PB => PA/PD=PF/PB => △PAF~△PDB(SAS)04/21 03:04