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作者 ybite 在 PTT [ Grad-ProbAsk ] 看板的留言(推文), 共154則
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1F→:排容原理問題02/22 13:33
2F→:分別討論一對、兩對...n對坐在一起的情況來討論02/22 13:35
3F→:小黃的習題有這題02/22 13:35
3F→:做I/O的時間CPU什麼都不能做,所以I/O Time=CPU idle time..02/21 12:44
6F→:我本來也想這樣寫,就是卡一個流量,所以沒寫下去...02/19 22:17
9F→:理解,16分飛了qqqqqqqqqqqqqq02/19 23:01
17F→:@doom8199 我題目沒記對,他不是Square matrix!?02/19 21:56
18F→:另外這題詳細希望qq02/19 22:00
1F→:我覺得答案是102/17 10:36
2F→:Multi-cycle是「有的指令快、有的指令慢」之下的解決方案02/17 10:36
3F→:ㄟ等等,我覺得我選錯了...orz02/17 10:39
1F→:(B)我是覺得不一定。因為假如他沒有記錄Tail的Pointer的話,02/16 12:44
2F→:光要找到Tail就要O(n)的時間,這時放在Head還比較經濟。02/16 12:44
3F→:(D)再複雜都是O(n)找+O(1)砍,應該還相同Time Complexity?02/16 12:46
3F→:1/(1-x) 是 1 1 1 1 1 1 1 .... 我也覺得答案應該是True02/16 11:50
6F→:啊,對,中計了XD02/15 08:49
8F→:我是這樣想的:根據5(a),我們Single Cycle需要4+i ns02/15 19:39
9F→:更正,4+N ns,所以平均每個指令都需要4+5 ns吧?02/15 19:40
10F→:雖然我覺得我有可能是錯的...02/15 19:40
1F→:是一種Symmetric programming下進行排程的一種措施02/14 21:11
2F→:對於排程的項目特別指定其偏好的Processor,以避免當Process02/14 21:12
3F→:跳到其他Processor時Cache等資料切換的緩慢狀況02/14 21:13
4F→:(也就是每個Process盡可能只交給一個Processor做)02/14 21:13
5F→:另外,這個和Load balancing之間互相衝突02/14 21:14
6F→:恐龍書第八版這個在5.5.2 (P202)02/14 21:14
7F→:更正,Symmetric Multiprogramming (SMP)02/14 21:14
5F→:我覺得考了也沒有幾個人會qqqqqqq02/14 22:24