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作者 Vulpix 在 PTT [ Math ] 看板的留言(推文), 共7171則
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1F→: 就是按照你說的:做偏微分。04/19 14:26
2F→: 是不會微分嗎?04/19 14:26
3F→: 還是函數寫不出來?04/19 14:27
5F→: cos(Argz)=x/|z|,sin(Argz)=y/|z|,隨便一條拿去04/19 14:56
6F→: 算微分就可以了。04/19 14:56
2F→: 會計算到這個級數應該學不少數學了,答案是π^2/6。04/19 14:21
2F→: 又想到一個用maximum modulus thm.的作法了哈。04/22 15:12
3F→: 若a!=0, f(-b/a)=0 => f(z)/(az+b) is entire04/22 15:16
4F→: (其實好像是用Liouville's thm.)04/22 15:18
5F→: f(z)/(az+b) is bbd. by |az+b|^-0.504/22 15:19
6F→: 在 z=-b/a 那附近也沒關係,因為 f(z)/(az+b)04/22 15:20
7F→: entire,所以連續,所以那附近也被限制住了。04/22 15:21
8F→: 所以可以找到 f(z)/(az+b) 的 global bound04/22 15:22
9F→: 因此 f(z) = c(az+b),代回原式比較係數就OK了。04/22 15:24
13F→: 其實文中的作法...[ 1 + (a/b)z ]^0.5只是記號而已04/23 01:30
14F→: 實做就是設a_n解方程,所以其實沒什麼須要抖的。04/23 01:30
1F→: 應該要用弧長參數重新參數化。04/18 22:15
1F→: 會讓函數壞掉的地方在z=-b/a,在這裡展開就可以了。04/18 21:07
2F→: 你在0展開會做不出來是因為:f在0是analytic,甚至04/18 22:02
3F→: 可以展開到接近-b/a,收斂半徑是|b/a|。04/18 22:02
4F→: 其實也可以在0展開,然後算收斂半徑來得到矛盾。04/18 22:10
2F→: 在沒講三角函數的微積分的情況下,不能直接積分。04/18 20:53
3F→: 有學指對數函數的微積分也行,但高中是不提的。04/18 20:54
2F→: 讚!04/18 00:39
12F→: 一對三角板的話,那個角度好像離42度有點遠。04/13 14:55