作者查詢 / kimkimkimkim
作者 kimkimkimkim 在 PTT [ Grad-ProbAsk ] 看板的留言(推文), 共108則
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1F推:應該沒錯 但我之前是把U是以歸一正交向量組成08/03 00:12
2F→:U^(-1) = U^(T) 這樣不知道有無較快08/03 00:13
2F推:拆成兩項很難看出來XD07/30 21:57
1F推:是不是不只一組答案07/30 16:59
2F→:請問有答案嗎?07/30 17:01
4F推:對角化出來答案很醜 有a和b的函數07/30 17:37
20F推:用a、b表示是唯一 但會開4次方根 寫1/4次方就好07/31 01:27
21F→:不過還是很煩07/31 01:27
9F推:部分分式後 三項都去求係數 應是要用到排列組合C去算07/30 16:23
10F→:係數吧 是這樣嗎?07/30 16:24
12F推:奇怪我怎算1/207/30 17:48
13F→:你算出來的係數 可以用無窮級數展開吧07/30 17:50
14F→:抱歉 我也算是1欸07/30 17:53
3F推:隨便擺沒差但順序要跟特徵向量一樣就好07/27 20:44
4F→:第二個 特徵向量加負號沒差 負號可放入或從未定係07/27 20:50
5F→:數07/27 20:50
6F→: 提出07/27 20:50
1F推:我想你應該翻書07/24 00:59
2F→:第二張圖積分就是第三張圖= =07/24 01:00
7F推:1/(x^2*y^2)dxy = (x^2*y^2)^(-1)dxy =(xy)^(-2)dxy07/24 01:10
8F→:= -(xy)^(-1) = -1/xy 右邊同理 外家積分常數07/24 01:11
9F→:這樣應該看的懂吧07/24 01:12
4F推:微積分 羅畢達定理07/22 21:38
5F推:∫lnx dx = xlnx - ∫x dlnx =xlnx - ∫x * 1/x dx07/21 08:40
6F→: = xlnx - ∫1dx = xlnx - ∫1dx = xlnx-x+c07/21 08:42
7F→:答案是這樣嗎07/21 08:42
9F推:其實是我是用分部積分公式 ∫u dv = u*v-∫v du07/21 12:46
1F推:第一題 一階線性方程式07/18 01:59
2F推:第二題 dy = 2dx + √(y-2x+3) dx07/18 02:01
3F→:dy - 2dx = √(y-2x+3) dx07/18 02:02
4F→:d(y-2x) = √(y-2x+3) dx07/18 02:02
5F→:du = √(u+3) dx , u = y-2x07/18 02:03
8F推:第一題沒要分開阿 乘上積分因子07/18 16:43
5F推:帶一組數字下去驗證即可07/16 13:30
6F→:分母應該除以兩次無誤07/16 13:31
14F推:.......07/16 23:08
15F推:分子是r ~ r-n+1項 並非r ~ 1 項 1~n 項與分母n!已07/16 23:10
16F→:約分07/16 23:10