Re: [積分] 極限
※ 引述《olala313 (喔耶耶)》之銘言:
: 1 x 2
: lim -----∫ cos t dt
: x→0 x 0
: 1 2 0
: = lim -----* sin x (-----)
: x→0 x 0
: 2
: = lim cos x * 2x
: x→0
: =0
: 想請問這樣做對嗎?
1 x 2
lim -----∫ cos t dt
x→0 x 0
d x 2
--- lim ∫ cos t dt
dx x→0 0
= ----------------------
d
--- lim x
dx x→0
2
= lim ( cos x ) * 1
x→0
=1
btw.這題是因為上限對x微是1,下限是0
所以看起來像是直接代入,
要是上限是g1(x),則最後一行要改成f(g1(x))*g1'(x)
下限要是不幸也是x的函數g2(x),
則改成f(g1(x))*g1'(x)) - f(g2(x))*g2'(x)
--
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