Re: [問題] 靜電場裡儲存的能量是光子能量嗎 ?
: → pp2009:這些都是想得到的概念, 但是要湊出 E^2/2 的能量密度 09/14 13:10
: → pp2009:你必須解釋那一鍋 "光子湯" 裡究竟有哪些料 ? 09/14 13:11
要看待這個問題,可以由古典電磁學的角度切入:
何謂能量密度 u = 1/2 (ε_0 E^2 + B^2/μ_0)
以及能量密度 u 從 0 充至 1/2 (ε_0 E^2 + B^2/μ_0) 過程中,發生哪些事
這時我們引入一條守恆式:
du/dt + ▽.P + J.E = 0
其中 u = 1/2 (ε_0 E^2 + B^2/μ_0) 為能量密度
P 為 Poynting vector (P = 1/μ_0 ExB)
J 為電流密度
p.s. 完整的守恆式要考慮 electromagnetic stress-energy tensor T^μν
D_μ T^μν + η^μρ f_ρ = 0
其中 D_μ 為對μ分量偏微
η^μρ = diag[-1, 1, 1, 1]
而 u = T^00
P = [T^01 T^02 T^03]
在 source free 的情況下,J= 0
所以,du/dt = -▽.P (under source free condition)
從古典電磁學可知,P即為電磁波通過單位面積能量傳遞的功率
P/c^2 即為電磁波單位體積的動量
du/dt = -▽.P 一式,恰好說明
單位體積內電磁場能量時變率,等於P進入該單位體積的量
(使用 divergence theorem)
這麼說吧,能量密度 u 從 0 充至 1/2 (ε_0 E^2 + B^2/μ_0) 的過程
就是電磁波透過 Poynting vector P 將能量帶入那一小塊的區域內
帶入能量的電磁波可以是高頻的電磁波,也可以是極低頻的電磁波
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