[微積] 一題積分
Find the area of the part of the cone z^2=x^2+y^2 lies inside
the cylinder x^2+y^2=2ay
我是這樣算的：
dz/dx = x/z, dz/dy = y/z ds=√2dxdy
let x=rcosw,y=rsinw--->r=2asinw
2pi 2asinw
∫zds =√2 ∫ dw∫ r^2dr
0 0
但是算出來跟答案不同，不知道哪裡錯了
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nmnmnmn囧 nmnmnmn囧 nmnmnmn囧 ┌─┐ c(￣ω￣ )οc(￣ω￣ )οc(￣ω￣ )
nmnmnmn囧 nmnmnmn囧 nmnmnmn囧 │八│ c(￣ω￣ )οc(￣ω￣ )οc(￣ω￣ )
nmnmnmn囧 nmnmnmn囧 nmnmnmn囧 │卦│ c(￣ω￣ )οc(￣ω￣ )οc(￣ω￣ )ο
nmnmnmn囧 nmnmnmn囧 nmnmnmn囧 │板│ c(￣ω￣ )οc(￣ω￣ )οc(￣ω￣ )ο
nmnmnmn囧 nmnmnmn囧 nmnmnmn囧 │聚│ c(￣ω￣ )οc(￣ω￣ )οc(￣ω￣ )ο
nmnmnmn囧 nmnmnmn囧◇祖國席◇ └─┘ ○深山席○ c(￣ω￣ )οc(￣ω￣ )ο
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