[理工] 複變
1.f(z)=sinhz/[(z-1)^2]，請問一下對1展開為啥是 │z-1│< ∞?
2.f(z)=[z^(1/2)]/z(z^2+1),題目問f(z)在 1<│z-1│< 2 是否解析
解答寫說f(z)在1<│z-1│< 2為多值函數，故f(z)不可解析
請問一下解答怎麼判斷的?謝謝
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