Re: [理工] [工數] 一階ODE
※ 引述《monkps ()》之銘言:
: y'+y=x/y
: 沒頭緒...
: 給我一點提示就好 XD
原本想說回應給提示就好...
因為看見n大的回文...讓我也想分享一下了
2
yy'+y = x
2 2 2
(y )' + 2y = 2x ___(視為y 的一階線性ode)
2 2x 2x
[y *e ]' = 2x*e
2 -2x 1
∴y = c*e + x - ─ then c is constant
2
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10/10 22:39, , 1F
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※ 編輯: mp8113f 來自: 125.224.71.200 (10/10 22:40)
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