[理工] [工數] ODE
這題解到一半卡住...
solve xp^2 - 2yp + 4x =0 p=y'
xp 2x
我移項成 y=－ + －
2 p
然後一起微分 p= p/2 + xdp/2dx + 2/p - (2x/p^2)dp/dx
整理>>> 0=(p/2 - 2/p)( 1+ xdp/dx)
然後我就不會了~"~...想請問接著要怎麼處理
答案是 cy=x^2 + c^2
另外一個是解 y" + 4y = sin2t y(0)=y'(0)=0
這題我算出來的答案怪怪的 想問一下解題的方法
謝謝大家~
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