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作者 attomahawk 在 PTT [ Math ] 看板的留言(推文), 共40則
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1F推:推薦這個 引導式思考流程。 : )04/13 09:13
3F推:推樓上,順便補個參考資料:http://0rz.tw/z2FKC04/02 01:17
4F推:由最小公倍數[ 3445 , 1643 ]= 10679504/02 01:34
5F→:分別除以 3445 和 1643 得到 商 31 和 65 。04/02 01:35
2F推:(3445,1643) = 5304/02 00:24
3F→:53 = 1643 - 10*15904/02 00:25
4F→:53 = 1643 - 10*( 3445 - 2*1643 )04/02 00:26
5F→:53 = 1643 - 10*3445 + 20*164304/02 00:26
6F→:53 = 21*1643 - 10*344504/02 00:27
7F推:調整係數為題目要求04/02 00:30
8F→:53 = ( 21 + 3445t )*1643 + ( -10 - 1643t )*344504/02 00:32
9F推:抱歉,我上一行推文推錯了!請看樓下那篇。04/02 00:35
1F推:推一個,我也是用這解法。04/01 23:50
2F推:B^2 = I = B * B04/01 21:36
3F→:B 剛好是 B自己 的 反矩陣B^(-1)。04/01 21:36
1F推:因為 A 為 Singular => det(A) = 0 且 A^(-1)不存在04/01 19:20
2F推:A*adj(A) = det(A)*I = 數字0 * 單位矩陣 = 零矩陣04/01 19:22
1F推:#2. #3. 的 證明:04/01 19:45
2F→: http://0rz.tw/crEmE04/01 19:45
3F→:#2. #3. 兩題證明過程類似,可類推。04/01 19:46
1F推:推薦這個解法!03/28 19:21