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[問題] 一個MIPS指令的問題

[ ASM ]6 留言, 推噓總分: +3

作者: skyhigh8988 - 發表於 2011/04/05 13:51(14年前)

1^F推attomahawk:lui 載入 Address的上半部, 從31bit 到 16 bit。04/05 14:20

2^F→attomahawk:ori 載入 Address的下半部, 從15 bit 到 0 bit。04/05 14:20

3^F推attomahawk:如此一來，暫存器t1 才擁有完整的 32-bit address.04/05 14:23

4^F→attomahawk:可以參考白算盤(Computer Org. and Design )的課本。04/05 14:23

5^F→attomahawk:我的是英文版 3ed, 在p.96 有類似的課本例子。04/05 14:25

[請益] .IF述句哪裡有錯

[ ASM ]11 留言, 推噓總分: +5

作者: shangclock - 發表於 2011/03/27 15:29(14年前)

6^F推attomahawk:樓上也是113呀。03/31 00:17

7^F推attomahawk:斷行宣告變數有接","的話，可以接下一行的數值。03/31 00:25

8^F→attomahawk:我的環境是 MASM + VS2010。03/31 00:26

11^F推attomahawk:^^04/01 18:46

[問題] 自然數開平方

[ ASM ]4 留言, 推噓總分: +1

作者: loteslogin - 發表於 2011/03/04 16:01(15年前)

1^F推attomahawk:可以試試看 Newton-Raphson 迭代逼近法，03/28 00:51

2^F→attomahawk:初始值Xo 可以用 ( eax/2 )，03/28 00:51

3^F→attomahawk:此方法的特性是迭代數列會自動收斂到 sqrt(x) 。03/28 00:52

4^F→attomahawk:收斂比例也滿漂亮的。03/28 00:52

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