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作者 Vulpix 在 PTT [ Math ] 看板的留言(推文), 共7171則
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5F→:還是推薦叫特解,因為每個解都是非齊性解,用這個名07/22 17:17
6F→:字總覺得讓人有點摸不著頭腦。而特解,指的是我們07/22 17:18
7F→:特別選出來的那一個解(是個非齊性解)。07/22 17:19
1F→:其實...還好,因為右式也是個瑕積分XD07/20 13:40
2F→:所以這個等號也是"in some sense",那就只要計算時的07/20 13:41
3F→:"sense"跟這個等號需要的"sense"相同即可。07/20 13:41
8F→:我有點想知道...i難道應該當成變數嗎?@@07/20 21:23
1F→:大概是傅立葉轉換一下,交換積分順序就做出來了吧?07/20 09:43
1F→:log(x)/(x-1)這部份是普通的微積分習題,極限是1。07/19 21:20
2F→:剩下的 [一坨積分]/(x-1) 請用微積分基本定理。07/19 21:21
8F→:話說你的第一題應該能知道你那樣分是不行的^^|||07/19 21:41
9F→:應該要分成n堆啊,這樣任取n+1個才會有兩個同堆07/19 21:42
1F→:1.選v=(-i-1,0,2)去算v'Av就知道了...07/25 13:29
2F→:再說,你的三階行列式算錯了,理應非正。(Ans:-1)07/25 13:30
3F→:2.1/(e^st*sqrt(t))的在原點附近的瑕積分收斂07/25 13:32
4F→:你會誤會是因著眼點錯誤,D的理由中"且"字後的說明07/25 13:33
5F→:才是比較重要的部份,前面是前製作業。07/25 13:33
6F→:3.對07/25 13:33
4F→:"三次式","三個根"...我想你大概想用代數基本定理之07/18 19:53
5F→:類的,可是這不能這樣用。07/18 19:53
6F→:如果是這樣:|R(x,y,z)[w]中的多項式 f(w)07/18 19:57
7F→:f(w)=xyz-(yz+xz+xy)w+(z+y+x)w^2-w^307/18 19:57
8F→:然後因為f(x)=f(y)=f(z)=0,所以由因式定理blablabla07/18 19:58
9F→:那就可以07/18 19:58
1F→:(x,z)=1 的時候,(x,yz)=(x,y)。07/17 16:10
4F→:一樣的理由...(x,z)=1 的時候,(x,y)=(x,yz)。07/17 16:46
7F推:一個常見的 resolution of identity 吧07/15 13:12