[解題] 機率
1.年級:高職二年級
2.科目:數學
3.章節:機率
4.題目:
一間公司錄取一名員工,假設甲錄取的機率是1/3,乙錄取的機率是1/4,
請問甲或乙錄取的機率為何?
5.想法:
第一種:
P = P(甲錄取乙沒錄取) + P(甲沒錄取乙錄取)
= 1/3 * 3/4 + 2/3 * 1/4
= 5/12
第二種:
甲與乙交集為0 為互斥事件
P = 1/4 + 1/3
= 7/12
我想了很久還是找不出哪一種有問題,請教各位了,謝謝。
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 118.171.65.207
推
05/12 01:46, , 1F
05/12 01:46, 1F
推
05/12 01:51, , 2F
05/12 01:51, 2F
→
05/12 01:52, , 3F
05/12 01:52, 3F
→
05/12 01:53, , 4F
05/12 01:53, 4F
→
05/12 01:54, , 5F
05/12 01:54, 5F
→
05/12 01:56, , 6F
05/12 01:56, 6F
→
05/12 01:57, , 7F
05/12 01:57, 7F
→
05/12 01:57, , 8F
05/12 01:57, 8F
→
05/12 01:59, , 9F
05/12 01:59, 9F
討論串 (同標題文章)