討論串[積分]
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x^2. ∫ (e^(t^2) + 4) dt. 0. lim ------------------------. x→0 (sinx)^2. (2x)(e^(x^4) + 4). = lim --------------------. x→0 (2)(sinx)(cosx). (2x)(e^(x^
(還有172個字)
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x. f(x) = ∫ f(t) dt + 2. 0. d(f(x)). --------- = f(x). dx. d(f(x)). --------- = dx. f(x). ln|f(x)| = x + c_1. |f(x)| = e^(x+c_1) = (e^(c_1))(e^x). f(x
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令 u = ln(x^2 + 2x + 2) , dv = dx. 2x + 2. 則 du = -------------- dx , v = x. x^2 + 2x + 2. ∫ln(x^2 + 2x + 2) dx. 2x + 2. = (x)(ln(x^2 + 2x + 2)) - ∫(x)
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令 t = √x , 則 x = t^2 => dx = (2t) dt. ∫ cos(√x) dx. = ∫ (cos(t))(2t) dt. = (2)(∫(t)(cos(t)) dt). = (2)((t)(sin(t)) - ∫sin(t) dt). (令 u = t , dv = cos(
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