[積分] 不定積分
x arcsinx
S----------dx=?
(1+x^2)^2
解答第一行:
-arcsinx 1
--------- +S----------------------dx
2(1+x^2) 2(1+x^2)(1-x^2)^(1/2)
...
...
最後答案是:
-arcsinx 2^(1/2) 2^(1/2) x
--------- + -------- arctan----------------dx + C
2(1+x^2) 4 (1-x^2)^(1/2)
看不懂解答第一行是怎麼變出來的.謝謝!
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