[中學] 指數
學生有一題
[(-3)^(1/2)]^4 = (-3)^2 答案是錯的
不過我將左式如果用隸美弗
(-3)^(1/2)=[3(cos(pi)+i*sin(pi))]^(1/2)
=sqr(3)*[cos(pi/2+k*pi)+i*sin(pi/2+k*pi)] k屬於Z
[(-3)^(1/2)]^4 = 3^2 * [cos(2pi+4k*pi)+i*sin(2pi+4k*pi)]
= 9 * 1 =9
跟右式相等
請教版上神人...小弟的問題出在哪裡??
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