※ 引述《justin0602 (justin)》之銘言:
: π^3 和 3^π誰大
: 有什麼好方法處理這問題
a a a
(a(1+b)) = a (1+b)
a(1+b) a ab
a = a a
Let a = 3, b = (π - 3) / 3
Then a > e, b > 0
b b
=> a > e > 1 + b
a(1+b) a
=> a > (a(1+b))
=> 3^π > π^3
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◆ From: 114.32.58.129
※ 編輯: mgtsai 來自: 114.32.58.129 (09/07 09:32)
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