Re: [微積] 分部積分
※ 引述《s511320 (幻境)》之銘言：
: 兩年沒碰微積分了
: 朋友突然丟一題給我 也不知道怎麼解
: 但好像是分部積分的樣子
: x -y -2x-y
: e y dy/dx = e +e
: x -y -2x
: e y dy/dx = e (1+e )
: y -x -2x
: ye dy = e (1+e )dx
left: let y=u,e^ydy=dv,dy=du,v=e^y--->ye^y-e^y
right:e^(-x) + e^(-3x)--->-e^(-x) - 1/3e^(-3x)
兩邊積分後可得ye^y-e^y = -e^(-x) - 1/3e^(-3x)
--
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