Re: [代數] integral domain
1.Prove Zp is a division ring (As I prove aboved)
2.Assume there exists [a],[b] 均=/= [0]
But [a][b]=[0]
From 1. there exists [a]^-1 s.t. [a][a]^-1=[1]
so [a]^-1[a][b]=[a]^-1[0]
=> [b]=[0] , →←
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12/27 23:18, , 1F
12/27 23:18, 1F
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