[理工] 線代
[ 5 3cos(7/6*pi) 3cos(14/6*pi) 3cos(21/6*pi) 3cos(28/6*pi) 3cos(35/6*pi)]
[3cos(7/6*pi) 5 3cos(7/6*pi) 3cos(14/6*pi) 3cos(21/6*pi) 3cos(28/6*pi) ]
[3cos(14/6*pi) 3cos(7/6*pi) 5 3cos(7/6*pi) 3cos(14/6*pi) 3cos(21/6*pi) ]
A=
[3cos(21/6*pi) 3cos(14/6*pi) 3cos(7/*6pi) 5 3cos(7/6*pi) 3cos(14/6*pi)]
[3cos(28/6*pi) 3cos(21/6*pi) 3cos(14/6*pi) 3cos(7/6*pi) 5 3cos(7/6*pi) ]
[3cos(35/6*pi) 3cos(28/6*pi) 3cos(21/6*pi) 3cos(14/6*pi) 3cos(7/6*pi) 5 ]
Find eigenvalues. A is 6*6, A = A^t.
這題是周易線代寫真秘笈4-2節的範例二
他是用最小多項式去解
但是看不太懂 A^2 - 13A + 22I = 0 怎麼來的
拜託各位了
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◆ From: 220.141.7.110
推
10/17 21:24, , 1F
10/17 21:24, 1F
→
10/17 22:52, , 2F
10/17 22:52, 2F
※ 編輯: shareing 來自: 220.141.7.110 (10/17 22:55)
→
10/17 22:54, , 3F
10/17 22:54, 3F
推
10/17 23:18, , 4F
10/17 23:18, 4F
答案是 11 和 2
※ 編輯: shareing 來自: 220.141.7.110 (10/18 02:49)
→
10/19 00:23, , 5F
10/19 00:23, 5F
推
10/21 17:57, , 6F
10/21 17:57, 6F
→
10/21 21:17, , 7F
10/21 21:17, 7F
→
10/21 21:20, , 8F
10/21 21:20, 8F
→
10/21 21:21, , 9F
10/21 21:21, 9F
→
10/21 21:22, , 10F
10/21 21:22, 10F
→
10/21 21:24, , 11F
10/21 21:24, 11F
推
10/23 16:11, , 12F
10/23 16:11, 12F
→
10/23 16:11, , 13F
10/23 16:11, 13F
→
10/23 16:18, , 14F
10/23 16:18, 14F
→
09/11 14:33, , 15F
09/11 14:33, 15F
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