Re: [理工] [工數][ode]
※ 引述《asdf322505 ()》之銘言:
: (2x+y^4)y'=y ,y(24)=2
原式 => 2xdy+y^4 dy = ydx
=> ydx-2xdy = y^4 dy
d(xy^-2)
=> ──── = y^4 dy
y^-3
=> d(xy^-2) = ydy
積分=> xy^-2 = 0.5y^2 + C
=> x = 0.5y^4 + Cy^2
帶入邊界條件求c = 4
得特解x=0.5y^4+4y^2
: ans:x=1/2y^4+4y^2
: 請問這要怎嚜解
: 請問你們都怎嚜判斷,ode該用什麼解法?
靠經驗,題目做多了自然知道怎麼解。
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