[問題] 我這樣很爛嗎?

看板C_and_CPP作者skizzy (活著是件難過的事)時間13年前 (2012/09/03 02:25)推噓9(9推 0噓 20→)

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把我應徵某公司考題的答案在這裡給這邊的大大鞭策使用編譯程式 codeblock C++ 1. There are four digits on the face of a 12‐hr digital clock. How many times in oneday (24 hours) can you see three or more of the same number in a row (e.g.,01:11, 02:22, etc) on the clock face? In addition, please use any programming language, pseudo‐code, or flow‐chart to write an algorithm to compute the answer. 2. Please design a rough architecture of an online paper‐scissor‐stone game. Be as imaginative as you can in terms of functionality and architecture. You may use UML or simple block diagrams for your design. 3. Please use any programming language, pseudo‐code, or flow‐chart to implement an algorithm for the following equation: Yn=Xn^2-Xn-1*Xn+1 1. answer: #include <iostream> #include <stdlib.h> using namespace std; int main() { int x,a, b, c, d, h, m; int t=0; for (x=0; x<720; x++) { h=x/60; m=x%60; a=h/10; b=h%10; c=m/10; d=m%10; if (a==b && a==c && a==d ) { t++; cout<<a<<b<<c<<d<<endl; } else if (a==b && a==c && a!=d) { t++; cout<<a<<b<<c<<d<<endl; } else if (a!=b && a==c && a==d) { t++; cout<<a<<b<<c<<d<<endl; } else if(a==b && a!=c && a==d) { t++; cout<<a<<b<<c<<d<<endl; } else if(c==b && a!=b && c==d) { t++; cout<<a<<b<<c<<d<<endl; } } cout<<t*2<<endl; cout<<x<<endl; system("pause"); return 0; } 2.answer: #include <iostream> #include <stdlib.h> #include <stdio.h> #include <time.h> using namespace std; void randomize() { time_t t; srand((unsigned) time(&t)); } int main(void) { randomize(); int x,y,z,r; cout << "請輸入你要出的拳種 0.剪刀,1.石頭,2.布" << endl; cin>>x; r=rand(); y=r%3; z=x-y; if (x==0) { cout <<"你出的是剪刀"<<endl; } } else if (x==1) { cout <<"你出的是石頭"<<endl; } } else if (x==2) { cout <<"你出的是布"<<endl; } } else { cout <<"請輸入0~2的整數"<<endl; } if (y==0) { cout <<"電腦出的是剪刀"<<endl; } } else if (y==1) { cout <<"電腦出的是石頭"<<endl; } } else if (y==2) { cout <<"電腦出的是布"<<endl; } if (z==0) { cout<<"平手"<<endl; } else if(z==-2||z==1) { cout<<"你贏了"<<endl; } else if(z==2||z==-1) { cout<<"你輸了"<<endl; } cout<<r<<endl; cout<<y<<endl; return 0; } 3.answer: #include <iostream> #include <stdlib.h> #include <stdio.h> using namespace std; int main() { int i,max,n; cout << "X(i)=1,0<=1<=N" << endl; cout << "Y(n)=X(n)*X(n)-X(n-1)*X(n+1)" << endl; cout << "0<n<N" << endl; cout << "N=?" << endl; cin>> max; n=max-1; int x[max],y[max]; for(i=0;i<max+1;i++) { x[i]=1; } for (i=0;i<n;i++) { y[i]=(x[i+1]*x[i+1])-(x[i+2]*x[i]); cout<<"y("<<i<<")="<<y[i]<<endl; } return 0; } 這樣很沒有邏輯架構嗎? 感覺很悶... 是不是接下來的programmer都會被打槍Q_Q -- ████ * http://ppt.cc/M9C4 臉書 http://0rz.tw/tkNbW 噗浪 ███◣ █ █ . ☆█ ◥█ ★ ，告訴你，我沒有朋友喔 ★ ████ ███ █ ☆ ◢███◣ ███◣ █ █ █ █ █ 你要當我的朋友嗎？ █──▄ █ █ █ ◢█ █ * █ ☆ █ §hilulu01 ★ ◥███◤*█ ☆█ ███◤ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.122.103.67

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legendmtg

09/03 10:37, , 1^F

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legendmtg

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mabinogi805

09/03 11:02, , 3^F

09/03 11:02, 3^F