作者查詢 / QQkimi
作者 QQkimi 在 PTT [ Grad-ProbAsk ] 看板的留言(推文), 共659則
限定看板:Grad-ProbAsk
看板排序:
全部Grad-ProbAsk659study323Examination211FongShan101graduate99StudyGroup69comm_and_RF10MP9PublicServan9GetMarry8Master_D8love-vegetal7learnyf6AllTogether4GO4NTPU-CSIE953NTUEE107HW3sex3V_ScHooL3Electronics2NCU97EE-B2need_student2NTU-EM932Violin2Bank_Service1Boy-Girl1CareerPlan1CCSH_92_3161CHNA-SW1CHU_ME92C1CPU_IM7311CTSH953031DaZhi6thH3021FCSH_Club1GraduateCram1HSJH_90_3021MCU_Talk1movie1NCU_Talk1NDHU-Ch991NDHU_MSE961NPTU1NSYSU1NSYSU_MSOE001NTUE-ME1001NUU_ME1PC26th3181PCSH96_3051RESIT1THU-P-Softbo1TransPhys1<< 收起看板(51)
4F推:...你還在解題壓XD 已經在職場了嗎?03/09 21:46
18F→:竟還可以在這裡見到元老doom大<(_ _)>10/20 12:04
1F推:好久沒碰...我印象好像是跟訊號擺幅極限有關09/30 17:08
4F推:恭喜原po高中榜首! 在這個版貢獻良多,好心有好報的^^b07/13 12:38
7F推:2(1)Ri 為了阻抗匹配impedence matching (2)gm = 2003/30 03:40
8F推:1.CMRR = 20log(Ad/Acm) ,20kHz 20log(Ad)=20-0.3*20=14dB03/30 04:05
9F→:樓上打錯 應該是20log(Ad/Acm)=14dB 又20log(Ad)=20dB03/30 04:07
10F→:=> 20log(Ad/Acm)=20log(Ad)-20log(Acm)=20-20log(Acm)=1403/30 04:08
11F→:=>20log(Acm)=6dB03/30 04:09
13F推:是靴帶環沒錯 去翻一翻史密斯應該有~02/24 18:44
32F推:<(_ _)>12/08 15:58
6F推:m(_ _)m 看到神要拜一下...09/11 11:34
5F推:...林教授的愛將! 逃...08/20 18:01
5F推:m(_ _)m06/16 09:38