作者查詢 / profyang
作者 profyang 在 PTT [ Math ] 看板的留言(推文), 共376則
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3F推:怎麼不太像線代...11/16 12:23
1F推:如果x<0,d(log(-x))/dx=-d(log(-x))/d(-x)=-(1/(-x))11/14 17:07
2F→:=1/x11/14 17:08
3F→:因為logx只對x>0有定義 所以x<0就要像我上面這樣11/14 17:08
4F→:這才是從微積分基本定理得到的1/x的導函數的完整結果11/14 17:09
5F→:因為1/x裡面x可以<011/14 17:09
6F→: 反11/14 17:10
11F推:x>0的你已經寫出來了d(log(x))/dx=1/x 然後x<0就我寫11/14 18:48
12F→:的 所以總結就是d(log(|x|))/dx=1/x for x=/=011/14 18:48
4F推:e^(lim(1/x))?11/12 23:05
5F→: x->∞11/12 23:05
10F推:我記得危機分裡有個定理是說可以 但要在連續的點11/12 23:15
11F→:x=∞不知道會不會不嚴謹 詳細定理敘述忘了11/12 23:15
13F推:找到了http://0rz.tw/Sq8xx 裡面的fact211/12 23:28
14F→:我沒記錯 這樣做確實是嚴謹的11/12 23:29
16F推:不是 你看那個連結的fact2 他是要你e^y在y=0連續11/12 23:58
17F→:y=lim(1/x)只要存在即可11/12 23:58
18F→: x->∞11/12 23:59
1F→:推這篇!其實就是用計算機寫loop!11/12 22:43
1F推:牛頓法?11/12 02:11
20F推:兩邊微分XDDD你微兩次就發現k=無限大了11/12 22:42
2F推:分別對x,y,z而言都是奇函數11/07 21:41
1F推:只要最後是實數就可以比阿11/07 00:10
4F推:剛去tutor版看了一整個囧 這是有啥好戰的...11/07 00:53
2F推:原PO你google大神算出來的是1F那個 但是你解的是11/06 01:27
3F→:((i^i)^i)^i....也就是x^i=x解x11/06 01:28
4F推:解答是錯的 你也是11/02 17:48
5F→:婀 下篇不是有人給正確答案了?11/02 18:05
9F→:好吧我收回我的話 感覺很可能是你照打解答打錯11/02 20:34
13F推:我只是在揣度他怎樣覺得他打的解答跟你一樣11/02 21:40