作者查詢 / LPH66
作者 LPH66 在 PTT [ Prob_Solve ] 看板的留言(推文), 共389則
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1F推:Σ_{i=1}^∞ 1/i^2 = π^2/6 所以那個和式小於一個常數11/09 17:40
2F→:http://en.wikipedia.org/wiki/Basel_problem11/09 17:41
1F推:_△∠ 左邊應該是你的 2) 的反例: deg 3 那點拿掉照斷10/30 23:40
2F推:3DES 的這種設計是為了相容原來的 DES 的10/22 16:13
3F→:當解密的鑰匙跟兩邊的加密鑰匙其中一邊相同時就會抵銷10/22 16:14
4F→:其效果就等同於原來只用一次加密的 DES10/22 16:14
5F→:>1F 3DES(msg,k1,k2,k3)=EnDES(DeDES(EnDES(msg,k1),k2),k3)10/22 16:16
6F→:原 PO 是在說這個設計為何不是使用三次 EnDES10/22 16:16
1F推:puzzle 版上有幾個 (包括我) 在解06/15 19:00
1F推:aa ab abaa05/13 23:10
2F→:奇的是 ab aa abaa 卻有正確答案...你的演算法顯然有些問題05/13 23:11
2F推:對電腦來說直接叫它暴力試 21 組會比用"人腦演算法"還快05/03 21:21
1F推:我的直覺你需要對你求出來的式子去做 mod 10^10 化簡04/27 02:33
2F→:不過因為還沒能仔細算有些東西可能不那麼容易...04/27 02:33
3F→:(例如你式子裡的分母如果是偶數那就沒這麼簡單了)04/27 02:33
4F→:啊我好像看懂你問題了...那就估計範圍吧04/27 02:34
5F→:估一下這個答案到底有沒有超過 10^10 去判斷04/27 02:34
1F推:先不論對錯, 你這是 O(n^2) 吧...04/21 20:57
2F→:再者 A = B = "abc" C = "abcabc" 好像是反例04/21 20:58
3F→:或者如果你覺得這個 C 太扯 那 "abacbc" 也可以04/21 20:59
4F推:唔, 實際跑你這段程式, 最簡單的 abc def adbecf 就炸了 XD04/21 21:03
7F推:嗯, 仔細想想後應該是線性沒錯, 不過正確性就...04/21 21:16
8F推:ok, 這程式碼裡有些打錯字的地方, 但即使修過後04/21 21:20
9F→:abc abc abcabc 跟 abc abc abacbc 都回傳 false04/21 21:21
10F→:更誇張一點的例包含 aaa aaa aaaaaa 也是你的演算法的反例04/21 21:22
1F推:提示: N 其實是 10M+k, 其中 k = 0~9, 所以 N-M 就是...?04/08 11:54
1F推:我第一個想到的是 Dithering, 不過這跟挑調色盤好像沒關係..03/30 01:45
2F→:(該說 Dithering 是挑完調色盤才在做的事)03/30 01:45