作者查詢 / LPH66
作者 LPH66 在 PTT [ Prob_Solve ] 看板的留言(推文), 共389則
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1F推: 這叫 Partition Problem 分堆問題, 它是 NP 完全05/07 15:04
2F→: 但有偽多項式做法 (ie. 數字總和的多項式時間)05/07 15:05
3F→: 咦等等我錯了, 這是 k-partition problem05/07 15:07
4F→: 這個沒有偽多項式做法...05/07 15:07
5F→: https://en.wikipedia.org/wiki/3-partition_problem05/07 15:07
18F推: 每組個數是給定且大家都一樣的 n 個05/07 21:36
19F→: 所以要求平均跟要求總和是一回事05/07 21:36
37F推: 有要求吧? 我引的那一頁的 3-partition 就是分成每組三個05/09 03:00
38F→: "..., can S be partitioned into m *triplets* S_1, ..."05/09 03:01
39F→: 所以它確實不只要求組數是三分之一, 每組個數也要求是三個05/09 03:01
2F推: k > 0 應該就對了, 所以你不能直接 % phi(n)02/05 21:30
2F推: 因為連線已經指定, 所以分子不是 8 而只有 101/03 19:17
3F→: 這跟隨便指定三格為中獎格是一樣的意思01/03 19:18
1F推: 90 度...寫這東西的人八成沒有算過直接抄解答 = =10/30 21:16
2F→: 30 度那個應該很好理解, 就是正切值 √3/3 的角度10/30 21:18
3F→: 所謂快速冪也就只是原 PO 的想法再進一步而已04/22 00:58
10F推: 就樓上的方法啦, 積分方式其實就是 prefix sum 而已04/22 00:56
11F→: 統計可以用例如 std::map 或 std::unordered_map04/22 00:56
9F推: flow 不會複製, 所以樓上那樣的 cap 3 永遠只會滿足至多 103/14 18:11
10F→: 原 PO 現在的問題就是在這裡03/14 18:11
1F推: 一個很初階的提示: 長除法10/11 03:21
2F→: 注意這不是叫你直接寫長除法, 原因如你所說時間是不夠的10/11 03:21
4F推: 本家費氏數列是取 1 或 2 個, 可以比較一下公式10/01 09:05
2F推: 先不管程式怎麼寫, 給你 13 張牌要你自己隨便組一個出來04/11 09:45
3F→: 你先把你自己分組的方式逐步寫下來再來考慮寫成程式04/11 09:45
4F→: 說隨便組是因為反正你只要組一組出來, 會不會贏不管04/11 09:46