Re: [積分] 一題積分
※ 引述《a50525004 (霧丸)》之銘言:
: S x/(x^2+2x-3)^1/2 dx
: 麻煩囉
1 2x+2 1
---∫---------------dx - ∫-----------------dx
2 (x^2+2x-3)^1/2 ((x+1)^2-2^2)^1/2
=> 左邊令t=x^2+2x-3,dt=(2x+2)dx
=> 右邊令u=x+1,du=dx
1 1 1
=> ---∫---------dt - ∫-------------------du
2 t^1/2 ((u)^2-2^2)^1/2
=> (t)^1/2-ln(u+(u^2-2^2)^1/2) + c
=> (x^2+2x-3)^1/2-ln((x+1)+(x^2+2x-3)^1/2) + c
我不確定對哦 = =
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※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 140.135.43.5
※ 編輯: momentaneous 來自: 140.135.43.5 (05/04 01:21)
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