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討論串[微積] 微分方程
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內容預覽:
y' = -exp(-x)y^2 + y + exp(x). => exp(x)y' - exp(x)y = -y^2 + exp(2x). => [exp(x)/y]' = 1 - [exp(x)/y]^2. => (1/2)ln[(y + exp(x))/(y - exp(x))] = x +
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內容預覽:
2 2 2. 2xy + 2xy + (x y + x )y' = 0. 2. 2xy(y+1)dx + x (y+1)dy = 0. x(y+1)[2ydx + xdy] = 0. 2. d(x y). x(y+1)-------- = 0. x. 2. (y+1) d(x y) = 0. 2 c
(還有604個字)