Re: [中學] 高中數學
: 請問這題怎麼解？
: 想取對數發現不行
: 不知如何下手謝謝
: -----
: Sent from JPTT on my iPhone
方便表示起見，令 a = 6 + sqrt(35)， b = 6 - sqrt(35)
A = a^2017 + b^2017
暴力二項式展開之後，有sqrt(35)的項會被消光光
因此每一項都是整數，A是個整數
由於 b 界在0和1之間，它的2017次方還是界在0和1之間
所以 M = A - 1
N = a^2017 - M
剩下懶的算(?)
--
嗯嗯ow o
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