Re: [分析] 一題求極限值
※ 引述《kyoiku (生死間有大恐怖)》之銘言:
: 設 a_n -> 5 as n -> oo
: b_n -> 3 as n -> oo
: Sigma(k from 1 to n-1) k(a_k)(b_(n-k))
: 求 lim ----------------------------------------
: n->oo n^2
: 就是 (a_1)(b_n-1) + 2(a_2)(b_n-2) + ... + (n-1)(a_n-1)(b_1)
: ------------------------------------------------------
: n^2
: 趨近於多少當 n 趨近於無窮大
對於任意給定小數ε << 1
必然可找到n > M, |a_nb_n - 15| < ε/ 3
a_1b_(n-1) + ... + Na_nb_(n-M) M(M + 1)15
必可找到n >= N, |-------------------------------- _ ------------| < ε/ 3
n^2 4 n^2
則當n >= max{N, M+1, 45/(2ε)}
(n + M)(n - M - 1)
|原式 - 15/2| ≦ ε / 3 + --------------------ε / 3 + ε / 3
2n^2
< ε
=> 極限值 = 15 / 2
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