[理工] [工數]-pde
這裡先用d當作偏微分
du/dt =d^2u/dx^2 +sinpix 0≦x≦1 1≦t
B.C.:u(0,t)=u(1,t)=0 I.C.:u(x,0)=1
答案是:4/pi〔(1-1/4pi)sinpix*e^((-pi^2)t)+(1/3)sin3pix*e^((-9pi^2)t)+.....〕+
﹏﹏﹏﹏﹏
(1/pi^2)()sinpix
不知是否是答案錯了 請各位工數高手幫幫忙
我算的答案是:4/pi〔﹏sinpix*e^((-pi^2)t)+(1/3)sin3pix*e^((-9pi^2)t)+.....〕+
(1/pi^2)()sinpix
請大家幫幫忙
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 122.116.10.35
推
08/23 19:34, , 1F
08/23 19:34, 1F
→
08/23 19:35, , 2F
08/23 19:35, 2F
→
08/23 19:36, , 3F
08/23 19:36, 3F
→
08/23 19:37, , 4F
08/23 19:37, 4F
→
08/23 19:37, , 5F
08/23 19:37, 5F
→
08/23 19:39, , 6F
08/23 19:39, 6F
→
08/23 19:40, , 7F
08/23 19:40, 7F
→
08/23 19:41, , 8F
08/23 19:41, 8F
→
08/23 19:42, , 9F
08/23 19:42, 9F
推
08/23 19:46, , 10F
08/23 19:46, 10F
→
08/23 19:49, , 11F
08/23 19:49, 11F
→
08/23 19:49, , 12F
08/23 19:49, 12F
→
08/23 19:51, , 13F
08/23 19:51, 13F
推
08/23 20:00, , 14F
08/23 20:00, 14F
推
08/23 20:05, , 15F
08/23 20:05, 15F
→
08/23 20:13, , 16F
08/23 20:13, 16F
推
08/23 20:22, , 17F
08/23 20:22, 17F
→
08/23 20:22, , 18F
08/23 20:22, 18F
→
08/24 00:15, , 19F
08/24 00:15, 19F
→
12/15 00:23,
5年前
, 20F
12/15 00:23, 20F
討論串 (同標題文章)