[理工] [工數]-拉氏轉換
g(t) = [ t^2 + n for t ≧ 0 , and 3n < t < 3n+3
[ 0 , if t < 0
solve L[g'(t)] = ?
我這樣轉可以嗎...
g'(t) = 2t [ u(t-3n)-u(t-3n-3) ]
然後取拉式 出來
2 * [ e^-3ns * (1/s^2 + 3n/s ) + e^-(3n+n)s * (1/s^2 + 3n+3 /s ) ]
感覺好奇怪.......
我也是過先轉g(t) 然後再用 sG(s)+g(0) 可是G(s)更醜...
請高手指點迷津...
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