[請益] 國二熱平衡的問題
我在作南一講義的習題時看到了很多這類的題目
想了很久卻都想不出來,故特別來此版詢問各位先進
題目如下:
將均為20g,25度c的鋁,銅,鐵三球,置於正在沸騰的水中並繼續加熱,
經一段時間後,溫度均停留在100度C,
已知鋁,銅,鐵的比熱分別為0.217,0.093,0.113cal/g-度c
自沸水中取出三球,分別放入三個裝有等質量且同為20度c水的紙杯中,
則各自達成熱平衡時,何者溫度最低?
很多參考解答都寫:因為銅比熱最小,溫度易升降,所以其平衡溫度會最低
但就我所知:
比熱小的物質溫度易升降是因為 H = msT 中, H與m一定, 所以s與T會成反比
反觀這一題 根本無法確定這三個金屬所放出熱量H是否固定
在只有質量m固定的情況下 要怎麼判斷溫差T的大小呢?
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