作者查詢 / OppOops
作者 OppOops 在 PTT 全部看板的留言(推文), 共2411則
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21F推: http://i.imgur.com/jiwrxIT.jpg01/04 15:33
5F推: XDDDD01/04 13:56
1F→: (1) p + p(1-p) + p(1-p)^2 , p = 3/401/03 17:06
2F→: (2) 1/601/03 17:07
2F→: bounded convergence thm + Rudin 7.17 thm01/03 01:35
8F→: 對不起我亂講 用樓上的三角不等式就好了01/03 01:54
4F推: [b1 b2 b3 b4] 必須屬於01/03 01:18
5F→: span{ [ 1 3 1 2], [-3, 1, 7, 4] }01/03 01:19
6F→: 然後上面這兩個向量線性獨立, 故x,y有解時, 解唯一01/03 01:24
7F→: span{v1, v2} 取自 C(A)01/03 01:26
12F→: 不是方陣沒辦法取det01/03 13:29
13F→: 當det(A^nxn)非0 <=> rank(A) = n <=> n組線性獨立01/03 13:33
14F→: 非方陣就去算reduced row echelon form01/03 13:34
1F→: 可以用indicator function來解釋01/01 23:49
2F→: 從Nk-1再丟一次確定到, 若是失敗從0開始所以(1-p)Nk01/01 23:54
1F推: 這些可以算的事件, 但是不滿足你隨機變數的觀察.01/01 12:04
2F→: 基本上必須算到停下來才算結束.01/01 12:05
3F→: 停下來: (1)已經傳了n次 (2)小於n次內已經成功01/01 12:05
4F→: 建議可以畫個n=2, n=3的樹狀圖來看01/01 12:09
7F→: 是01/01 21:04
1F→: xx 是 x^2 還是一個變數..?01/01 00:42
3F推: 我覺得是 y + 1/y = 5,求 y^2 + (1/y)^2 的形式01/01 19:10
4F→: 不然不太有漂亮的形式..01/01 19:11
6F→: 我的意思是 分母這樣出其實不太好算..01/01 22:56
2F→: (1)用手算的話, 同一樓12/31 00:06
3F→: (2)http://tinyurl.com/gp2hdeg12/31 00:06
4F→: 最簡單的就 n^2 + (n+1)^212/31 00:08
9F→: 原來如此, 難怪我記得好像沒有一個確定形式12/31 00:32