作者查詢 / kane950544
作者 kane950544 在 PTT [ trans_math ] 看板的留言(推文), 共33則
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全部ONE_PIECE62NARUTO43Math35trans_math33Transfer25Hunter22Gossiping16SCU_Talk13Physics10mobile-game8Bunco7CATCH6WorldCup6BLEACH4Hate4TransPhys4ChineseMed3sex3uni-talk3Anti-ramp2car2Eng-Class2GRE2Hokuto2joke2The-fighting2TOEFL_iBT2TOEIC2YUGIOH2C_Chat1CGSH86th3161ck61st3091cksh85th3171cksh85th3201CYCU_ICE90AB1Ecophilia1FCU_EE97A1HCHS543021HCSHch13_3111HSNU_11421ID_Multi1ILSH-963081L_SecretGard1media-chaos1Mind1NCCU-MATH941NCCU08_Math1NTU1NTUcourse1SSSH-16th3131StoneAge1Suckcomic1TaiwanScript1Taoyuan1Tea1tennisprince1THU-HIS971TigerBlue1trans_humans1tutor1Violation1<< 收起看板(61)
1F→:|x^0.5-a^0.5|=|x-a|/|x^0.5+a^0.5|111.249.9.29 10/12 20:22
2F→:私心推Salas~114.24.159.155 09/22 23:19
5F→:不好意思 是無窮級數 沒打清楚114.24.183.196 06/13 01:20
8F→:是要求值喔...而且是交錯級數的重排111.249.15.226 06/13 23:57
1F→:上下界趨近於無窮的速率不一定要一樣111.249.6.79 02/11 16:13
1F→:2.Let F(x)=f(x)-0.5[f(x1)+f(x2)]114.44.186.94 12/06 21:44
2F→:設f(x1)>f(x2),再用中間值定理114.44.186.94 12/06 21:46
3F→:b部分就取max和min之後用中間值定理吧114.44.186.94 12/06 21:47
4F→:Let M=Max(f1,f2,f3),m=min(f1,f2,f3)114.44.186.94 12/06 21:48
5F→:Is the equation f(x)-x=0是在問什麼?114.44.186.94 12/06 21:49
6F→:那就設F(x)=f(x)-x 利用f(x)的有界性114.24.172.124 12/09 23:40
7F→:F(x)→-∞ as x→∞114.24.172.124 12/09 23:42
8F→:F(x)→∞ as x→-∞114.24.172.124 12/09 23:42
9F→:由中值定理就可以了114.24.172.124 12/09 23:43
10F→:第一題定義域只有兩個點 我也看不懂114.24.172.124 12/09 23:44
1F→:f(x)=1/x111.249.5.175 12/06 22:34
2F→:0114.24.172.124 12/09 23:49
1F→:令F(x)={[f(b)-f(a)]/[g(b)-g(a)]}114.44.191.92 07/29 10:09
2F→:‧[g(x)-g(a)]-[f(x)-f(a)]再用ROLLE114.44.191.92 07/29 10:11
5F→:後面是xdx還是dx?114.44.179.13 07/23 08:48
3F噓:砍掉重練114.24.168.144 07/16 00:29