作者查詢 / alan23273850
作者 alan23273850 在 PTT 全部看板的留言(推文), 共15612則
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12F推: 當然是 1,語意蠻明確的03/22 11:05
29F推: 這個例子我覺得列車 30 秒來不及在阿婆墜落點之前03/01 02:09
30F→: 停下來03/01 02:09
5F→: 打逐字稿真的超花時間XD 比看影片的時間還要多02/18 20:59
6F→: 其實不是真的逐字,應該是重點整理加吸收,但差不多02/18 20:59
7F→: 意思,然後 MFLP 真的是大魔王,但也很有趣就是了02/18 21:00
14F→: 竟然釣到老師親自回覆!我現在回想起來那個時候疑慮02/19 21:14
15F→: 在哪了,那個時候我好像是問到說如果 client 一直被02/19 21:14
16F→: redirect 的話,那不等式右邊的常數倍就會累積,導02/19 21:15
17F→: 致 approximation ratio 會比預期的高上許多,所以02/19 21:15
18F→: 感覺無論是什麼版本,應該都要補上保證每個不等式都02/19 21:15
19F→: 只會被 apply 一次的理由才對。至於開 facility 的02/19 21:16
20F→: 時候到底要不要堅持從 cost 最小的開,當然從最小的02/19 21:16
21F→: 開一定是最安全,但我現在無力再追究詳細的證明了,02/19 21:17
22F→: 那部分就留給這學期的修課同學下去檢驗吧!02/19 21:17
22F推: 有修過嵌入式系統都知道 cross compile 吧!02/15 11:45
10F推:140.109.16.77 01/31 20:27
1F→: 我好像解出來了,答案是肯定的!我把原 obj 用連鎖01/17 01:14
2F→: 率以 r 為中間變數對 B 作微分之後,運用反函數的01/17 01:14
3F→: 微分公式消去一些項之後,剩下 -log2(f^-1(B)),又01/17 01:14
4F→: 根據 f 的函數圖形,B 固定的時候 d 遞增則 f^-1(B01/17 01:14
5F→: ) 遞減則 -log2(f^-1(B)) 遞增,此現象對每個 B 都01/17 01:14
6F→: 如此,因此 obj 從原點出發的時候就永遠是大的 d01/17 01:14
7F→: 贏了!01/17 01:14
8F→: 事實上 B 還必須 > 0 才行01/17 01:27
9F→: 如果還要更細緻的討論的話,就是這個函數在 B=0 和01/17 02:15
10F→: B>0 之間也許沒有連續,所以如果只依賴 B->0 時的01/17 02:15
11F→: 函數值 -> 0 for all d 的話,要怎麼 claim 大 d01/17 02:15
12F→: 的函數值較大還是個問題...01/17 02:15
14F→: 老師開口閉口都是 cover & thomas,還有另外幾本比01/17 10:55
15F→: 較次要的01/17 10:55
17F→: 那是 information theory 的課本不是 optimisation01/17 12:23
18F→: 專書01/17 12:23
20F→: 最後終於把整個問題全劇終,從原點極限搭配向右出01/18 17:59
21F→: 發的大小關係便可以 implies 函數永久的大小關係,01/18 17:59
22F→: OBJ 跟老師從作業結論 reduce 過來的解一模一樣,01/18 17:59
23F→: 老師真的猴腮雷!這小題的檢討我寫了四面答案卷,01/18 17:59
24F→: 希望其他題不會讓我這麼崩潰01/18 17:59
25F→: * 20F:向右出發的「斜率」大小關係01/18 18:00
26F→: 然後 B = 0 有唯一解 001/18 20:01
5F推:140.109.16.77 01/15 22:12
33F推:140.109.16.77 01/15 13:57
1F推:140.109.16.77 01/14 13:20
28F推: 推140.109.16.77 01/13 21:35