[解題] 高一 數學 三角函數
1.年級:高中一年級
2.科目:三角函數
3.章節:Ch2
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4.題目:在一個圓中,AB是直徑,P點在圓上異於A、B兩點,C點異於A、B兩點,且
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與P點不同側,若AB = 10,sin∠PCB = 3/5,則 PA + PB = ?
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5.想法:原本打算從 PA^2 + PB^2 = 10^2 去求解,但是怎樣也跟sin∠PCB找不到
牽連性,因此感覺上卡住了,不知道是不是題目有問題還是我想法錯誤?
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