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[ Math ]
討論串[中學]
共 51 篇文章
內容預覽:
假設題目是這樣. 首尾配對, 對首末兩項有. a^2/(a-1) + a^200/(a^100-1). = (a + 1 + 1/(a-1)) + (a^100 + 1 + 1/(a^100-1)). = a + a^100 + 2 + 1/(a-1) + 1/(a^100-1) (x^2/(x-1
(還有735個字)
內容預覽:
a + 2b = 4 - 3c. 2ab + 3c(2b + a) = 5. => 2ab + 3c(4 - 3c) = 5. => 2ab = 5 - 12c + 9c^2. (5 - 12c + 9c^2)/(a) + a = 4 - 3c. => a^2 + (3c - 4)a + (9c^2
(還有59個字)