Re: [中學] 一題三角函數?!
※ 引述《IAMYOURDAD (小句點)》之銘言:
: 題目是...
: 在三角形ABC中,AB=40,AC=31,sinA=2/5,此三角形內接於AQRS中,
: B在QR上,C在RS上,求矩形AQRS最大面積?!
: (想了很久沒什麼頭緒~....
令 ∠BAQ = α 、 ∠CAS = β ,得 α + β = 90 - ∠A
則 AQ = 40cosα 、 AR = 31cosβ
所以矩形面積 = 40 * 31 * cosα * cosβ
cos(α-β) + cos(α+β)
= 1240 * -------------------------
2
/ \
= 620 * | cos(α-β) + cos(90 - A) |
\ /
/ \
= 620 * | cos(α-β) + sinA |
\ /
/ 2 \
= 620 * | cos(α-β) + --- |
\ 5 /
故當 α = β 時,cos(α-β) 有最大值 1 ,此時面積 = 868 為最大值
P.S.
積化和差不在現今高中課綱中。
可以用和角公式取代之,但會牽扯到倍角與疊合公式而且很麻煩…
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※ 編輯: freePrester (118.160.209.156), 09/10/2016 02:47:22
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