Re: [中學]幾題高中數學

看板Math作者 (希望願望成真)時間11年前 (2015/02/22 23:23), 編輯推噓0(000)
留言0則, 0人參與, 最新討論串3/5 (看更多)
※ 引述《bingo7 (夏天)》之銘言: : 請教幾題高中數學,上次謝謝熱心的人 : 受益良多~ : 5.f(x)為三次多項式, f(x)除以x^2+x+2餘式為x+2, 除以x^2+x-2餘式為-x+2, : 求f(x)除以x^3+x^2的餘式為? f(x) = ax^3 + bx^2 + cx + d = a(x + 1)x^2 + (b - a)x^2 + cx + d = a[(x^2 + x - 2)x + 2x] + (b - a)x^2 + cx + d = a(x^2 + x - 2)[ax + (b - a)] + (c + 3a - b)x + (d + 2b - 2a) => c + 3a - b = -1 d + 2b - 2a = 2 = a[(x^2 + x + 2)x - 2x] + (b - a)x^2 + cx + d = (x^2 + x + 2)[ax + (b - a)] + (c - a - b)x + (d - 2b + 2a) => c - a - b = 1 d - 2b + 2a = 2 => a = b = -1 / 2 d = 2 c = 0 所以餘式 = 2 : 7.設三次多項式f(x)被(x^2-1)除之得餘式為2x+3 , 以(x^2+1)除之得餘式為-2x-1 , : 則f(x)=? f(x) = ax^3 + bx^2 + cx + d = (x^2 - 1)[ax + b] + (c + a)x + (d + b) => c + a = 2 d + b = 3 = (x^2 + 1)[ax + b] + (c - a)x + (d - b) => c - a = -2 d - b = -1 => c = 0 a = 2 d = 1 b = 2 => f(x) = 2x^3 + 2x^2 + 1 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 114.44.244.23 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1424618611.A.718.html
文章代碼(AID): #1KwVHpSO (Math)
文章代碼(AID): #1KwVHpSO (Math)