[微積] 三角函數微分
題目:y=2sin(3x)*cos(3x)
答案:6cos(6x)
小弟的想法:
y'=2*(3*cos(3x))*(-3six(3x))
=-18*cos(3x)*sin(3x)
然而為什麼答案會等於6*cos(6x)呢?不解?
麻煩版上前輩們不吝嗇指導,謝謝!
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※ 編輯: pigheadthree 來自: 114.46.135.246 (05/01 05:59)
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