[微積] 一題積分 int(x^2*exp(-a*x^2),-inf,inf)
如題
∞ 1
∫ x^2 * e^(-a*x^2) dx = -------- *(π/a)^0.5
-∞ 2*a
請問要如何積分呢
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∫udv = uv-∫vdu
我令 u=x^2 du=2xdx
dv=e^(-a*x^2)dx v=∫e^(-a*x^2)dx
其中∫vdu=∫(∫e^(-a*x^2)dx)*2xdx
=2∫∫x*e^(-a*x^2)dxdx
- 1
=2∫(------*e^(-a*x^2))dx
2*a
= - (1/a)*∫e^(-a*x^2)dx
∞
而∫ e^(-a*x^2)dx=(π/a)^0.5
-∞
再帶回還是覺得怪怪的
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