Re: [中學] 三角函數
※ 引述《adamchi (adamchi)》之銘言:
: 設n>=2,若(2^n-1)x=360度,則cosx*cos2x*cos4x....cos(2^(n-1)*x)=?
: 答:1/2^n
原式 * (sinx / sinx)
= (1/2)^n sin(2^n*x) /sinx
(2^n-1)x = 360
2^n * x = 360 + x
所以原式
= (1/2)^n sin(x)/sin(x)
= 1/2^n
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